Pattern In C Part 2

 

Output : 11

    1    
   1 2   
  1 2 3  
 1 2 3 4 
1 2 3 4 5_

Program : 11

  1. #include <stdio.h>
  2. #include <conio.h>
  3. void main() {
  4. 	int rw,c,no,spc;
  5. 	clrscr();
  6. 	printf("Enter number of rows : ");
  7. 	scanf("%d", &no);
  8. 	for (rw=1; rw<=no; rw++) {
  9. 		for (spc=no; spc>=rw; spc--) {
  10. 			printf(" ");
  11. 		}
  12. 		for (c=1; c<=rw; c++) {
  13. 			printf("%2d",c);
  14. 		}
  15. 		printf("\n");
  16. 	}
  17. 	getch();
  18. }

Output : 12

        1    
      1 2 3
    1 2 3 4 5
  1 2 3 4 5 6 7
1 2 3 4 5 6 7 8 9_

Program : 12

  1. #include <stdio.h>
  2. #include <conio.h>
  3. void main() {
  4. 	int i,j,k;
  5. 	clrscr();
  6. 	for (i=1; i<=5; i++) {
  7. 		for (j=1; j<=5-i; j++) {
  8. 			printf("   ");
  9. 		}
  10. 		for (k=1; k<=2*i-1; k++) {
  11. 			printf(" %d ",k);
  12. 		}
  13. 		printf("\n");
  14. 	}
  15. 	getch();
  16. }

Output : 13

 A B C D E F G G F E D C B A
   A B C D E F F E D C B A
     A B C D E E D C B A
       A B C D D C B A
         A B C C B A
           A B B A
             A A_

Program : 13

  1. #include <stdio.h>
  2. #include <conio.h>
  3. void main() {
  4. 	int i,j,asci,spc;
  5. 	clrscr();
  6. 	for (i=7; i>=1; i--) {
  7. 		for (spc=6; spc>=i; spc--) {
  8. 			printf("  ");
  9. 		}
  10. 		asci=65;
  11. 		for (j=1; j<=i; j++) {
  12. 			printf("%2c",asci++);
  13. 		}
  14. 		for (j=i-1; j>=0; j--) {
  15. 			printf("%2c",--asci);
  16. 		}
  17. 		printf("\n");
  18. 	}
  19. 	getch();
  20. }

Output : 14

AAA AAB AAC ABA ABB ABC ACA ACB ACC BAA BAB BAC BBA BBB
BBC BCA BCB BCC CAA CAB CAC CBA CBB CBC CCA CCB CCC_

Program : 14

  1. #include <stdio.h>
  2. #include <conio.h>
  3. void main() {
  4. 	char ch1, ch2, ch3;
  5. 	clrscr();
  6. 	for (ch1='A' ; ch1<='C' ; ++ch1) {
  7. 		for (ch2='A' ; ch2<='C' ; ++ch2) {
  8. 			for (ch3='A' ; ch3<='C' ; ++ch3) {
  9. 				printf(" %c%c%c", ch1, ch2, ch3);
  10. 			}
  11. 		}
  12. 	}
  13. 	getch();
  14. }

Output : 15

11111
2222
333
44
5

Program : 15

  1. #include <stdio.h>
  2. int main() {
  3. 	int i, j;
  4. 	for (i=1;i<=5;i++) {
  5. 		for (j=5;j>=i;j--) {
  6. 			printf("%d",i);
  7. 		}
  8. 		printf("\n");
  9. 	}
  10. 	return 0;
  11. }

Output : 16

1234567
12345
123
1

Program : 16

  1. int main() {
  2. 	int i,j;
  3. 	for (i=7;i>=1;i-=2) {
  4. 		for (j=1;j<=i;j++) {
  5. 			printf("%d",j);
  6. 		}
  7. 		printf("\n");
  8. 	}
  9. 	return 0;
  10. }

Output : 17

55555
45555
34555
23455
12345

Program : 17

  1. int main() {
  2. 	int i, j, k;
  3. 	for (i=5;i>=1;i--) {
  4. 		k = i;
  5. 		for (j=1;j<=5;j++) {
  6. 			if(k <= 5) {
  7. 				printf("%d",k);
  8. 			} else {
  9. 				printf("5");
  10. 			}
  11. 			k++;
  12. 		}
  13. 		printf("\n");
  14. 	}
  15. 	return 0;
  16. }

Output : 18

1
10
101
1010
10101

Program : 18

  1. #include<stdio.h>
  2. int main() {
  3. 	int i,j,k;
  4. 	for (i=1;i<=5;i++) {
  5. 		for (j=1;j<=i;j++) {
  6. 			printf("%d",j%2);
  7. 		}
  8. 		printf("\n");
  9. 	}
  10. 	return 0;
  11. }

Output : 19

12344321
123**321
12****21
1******1

Program : 19

  1. #include<stdio.h>
  2.  
  3. int main() {
  4. 	int i,j,k;
  5. 	for (i=4;i>=1;i--) {
  6. 		for (j=1;j<=4;j++) {
  7. 			if(j<=i)
  8. 			        printf("%d",j); else
  9. 			        printf(" ");
  10. 		}
  11. 		for (j=4;j>=1;j--) {
  12. 			if(j<=i)
  13. 			        printf("%d",j); else
  14. 			        printf(" ");
  15. 		}
  16. 		printf("\n");
  17. 	}
  18. 	return 0;
  19. }

Output : 20

5432*
543*1
54*21
5*321
*4321

Program : 20

  1. #include<stdio.h>
  2.  
  3. int main() {
  4. 	int i,j;
  5. 	for (i=1;i<=5;i++) {
  6. 		for (j=5;j>=1;j--) {
  7. 			if(i==j)
  8. 			        printf("*"); else
  9. 			        printf("%d",j);
  10. 		}
  11. 		printf("\n");
  12. 	}
  13. 	return 0;
  14. }

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